Answer:
Resultant = (0.54î - 1.75j) N
Magnitude = 1.83 N, Direction = - 72.9°
Explanation:
From the free body diagram, the resultant is a vector sum of all the three individual forces.
F₁ = 4(cos 25°î + sin 25°j) = (3.625î + 1.691j) N
F₂ = 6(cos 325î + sin 325j) = (4.915î - 3.441j) N
F₃ = (- 8î) N
Resultant force = F₁ + F₂ + F₃ = (3.625î + 1.691j) + (4.915î - 3.441j) + (- 8î) = (0.54î - 1.75j) N
Magnitude = √[(0.54²) + (-1.75²)] = 1.83 N
Direction = tan⁻¹ (-1.75/0.54) = - 72.9°
