Answer:
44.81 feet
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the right triangle ACD
Find the length side AC (height of the small fire tower)
[tex]tan(52^o)=\frac{AC}{50}[/tex] ---> by TOA (opposite side divided by the adjacent side)
Solve for AC
[tex]AC=tan(52^o){50}[/tex]
[tex]AC=64\ ft[/tex]
step 2
In the right triangle ABE
Find the length side AB
[tex]tan(21^o)=\frac{AB}{50}[/tex] ---> by TOA (opposite side divided by the adjacent side)
solve for AB
[tex]AB=tan(21^o){50}[/tex]
[tex]AB=19.19\ ft[/tex]
step 3
How many feet off the ground is the squirrel?
Subtract the length side segment AB from the length side segment AC
so
[tex]64-19.19=44.81\ ft[/tex]
Answer:
74.5561779772 feet
Step-by-step explanation:
1.) Tan(52)(a/50ft) ... ans = "distance from tower to tree" and your new adj at the angle of elevation from you to the squirrel.
2.) Tan(21)(a/63.9970816097) = x2 "remainder of tree/position of squirrel"
3.) ans#2 + 50ft "or x1" Â = "feet from ground and the squirrel."
comment: I got the exact same answer when I first tried to calculate it.
the reason the previous answer given is incorrect is because the angle between you and the squirrel is " elevated" not "depressed."
In such case. you must treat base of tree to your/tower height "50ft" as (x1) and the elevation of the squirrel as (x2) and then add them.
though I might be incorrect, for my knewton Alta has it as 88.4 or something crazy. there isn't an account for how tall the tree is. rationally I too would assume if I'm 50ft up in the air that both the tip of the tree and the squirrel might be at an angle of depression. Especially if there is 64ft between me and the tree . however the question clearly states that is not the case.
