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At 380 0C, the equilibrium concentrations are [CH3OH] = 0.20 M, [CO] = 0.35 M, and [H2] = 2.1 M for the reaction: CH3OH (g) ⇌ CO (g) + 2H2 (g) Calculate K at this temperature?

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sebassandin

Answer:

[tex]K_{eq}=7.72[/tex]

Explanation:

Hello,

In this case, for the given reaction, the law of mass action turns out:

[tex]K_{eq}=\frac{[CO]_{eq}[H_2]^2_{eq}}{[CH_3OH]_{eq}}[/tex]

Therefore, by considering the specified concentrations at the established temperature, the equilibrium constant turns out:

[tex]K_{eq}=\frac{0.35M*(2.1M)^2}{0.20M}=7.72[/tex]

Best regards.

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