Answer:
Pr(at least a girl) = [tex]\frac{7}{8}[/tex]
Step-by-step explanation:
Probability = Number of required outcomes / number of possible outcomes
We are to find the probability of at least one girl. assuming the likelihood of boys and girls are equal.
Pr( boy) = [tex]\frac{1}{2} =0.5[/tex]
Pr (three boys) = Pr(boy) * Pr(boy) *Pr (boy)
=0.5*0.5*0.5
=0.125
Pr ( at least a girl) = Pr (not getting a boy)
Pr(at least a girl) = 1- Pr(three boys)
Pr(at least a girl) = 1-0.125
Pr(at least a girl) = 0.875
Pr(at least a girl) = [tex]\frac{7}{8}[/tex]
The probability that when a couple has six children, at least one of them is a girl is 63/64.
Given
The probability is that when a couple has six children, at least one of them is a girl.
The probability distribution gives the possibility of each outcome of a random experiment or event.
The probability of them being a girl is 1/2.
Then,
The probability that when a couple has six children, at least one of them is a girl is;
[tex]= 1- \left (\dfrac{1}{2} \right ) ^6\\\\= 1 -\dfrac{1}{64}\\\\=\dfrac{64-1}{64}\\\\=\dfrac{63}{64}[/tex]
Hence, the probability that when a couple has six children, at least one of them is a girl is 63/64.
To know more about probability click the link given link below.
https://brainly.com/question/795909
