Answer:
[tex]a_c=1.44\ m/s^2[/tex]
Explanation:
Centripetal Acceleration
It's the acceleration that an object has when traveling on a circular path to take into consideration the constant change of velocity it must have in order to keep going in the circular path.
Being v the tangent speed, and r the radius of curvature of the circle, then the centripetal acceleration is given by
[tex]\displaystyle a_c=\frac{v^2}{r}[/tex]
We can compute the value of v by using the distance and the time taken to travel:
[tex]\displaystyle v=\frac{x}{t}=\frac{200\ m}{26.4\ s}[/tex]
[tex]v=7.58\ m/s[/tex]
Now we calculate the centripetal acceleration
[tex]\displaystyle a_c=\frac{7.58^2}{40}=1.44\ m/s^2[/tex]
[tex]\boxed{a_c=1.44\ m/s^2}[/tex]
