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Sulfur (S) and fluorine (F) form several different compounds. One of them, SF6, contains 3.55 g of F for every gram of S. Use the law of multiple proportions to determine n, which represents the number of F atoms in SFn, given that it contains 2.37 g of F for every gram of S.

Respuesta :

Edufirst

Answer:

     [tex]\large\boxed{\large\boxed{n=4}}[/tex]

Explanation:

You are given the mass ratio for SF₆.

                [tex]\dfrac{\text{mass of F}}{\text{mass of }S}=\dfrac{3.55}{1}[/tex]

Formula: Mass in grams = molar mass × number of moles:

              [tex]\dfrac{6\times \text{molar mass of F}}{1\times \text{molar mass of S}}=\dfrac{3.55}{1}[/tex]

Then:

              [tex]\dfrac{\text{molar mass of F}}{\text{molar mass of S}}=0.5916\overline 6[/tex]

Now, for SFâ‚™ you can write:

                [tex]\dfrac{n\times \text{molar mass of F}}{1\times \text{molar mass of S}}=\dfrac{2.37}{1}\\\\\\n\times 0.591\overline 6=2.37\\\\\\n=2.37/0.591\overline 6=4.00\\\\\\n=4[/tex]

Hence, n = 4 and the compound is SFâ‚„.

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