Respuesta :
Complete Question:
How many formula units of sodium nitrate will react with 25.0 g of calcium carbonate to product sodium carbonate and calcium nitrate according to the following reactions?
2 Na(NO3) + Ca(CO3) → Na2(CO3) + Ca(NO3)2
Answer:
[tex]3.011 \times 10^{23}[/tex] formula units of sodium nitrate will react with 25.0 g of calcium carbonate to produce sodium carbonate and calcium nitrate according to the equation.
Explanation:
Given chemical equation:
[tex]2 \mathrm{Na}\left(\mathrm{NO}_{3}\right)+\mathrm{Ca}\left(\mathrm{CO}_{3}\right) \rightarrow \mathrm{Na}_{2}\left(\mathrm{CO}_{3}\right)+\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}[/tex]
Given mass of calcium carbonate = 25 g
We need to determine the number of formula units of sodium nitrate that will react with 25 g of calcium carbonate.
Step 1: To calculate the number of moles of Calcium carbonate
Number of mole is the ratio of mass to the molar mass, given as
[tex]number\ of\ moles\ of\ Calcium\ carbonate =\frac{\text { mass }}{\text { molar mass of calcium carbonate }}[/tex]
molar mass of calcium carbonate = 100.0869 g / mol
[tex]\text {number of moles of Calcium carbonate}=\frac{25}{100.0869}=0.25 \text { moles }[/tex]
Step 2: Moles of Sodium nitrate that reacted
From the equation, 2 moles of NaNO₃ reacts with 1 mole of CaCO₃
Thus, the mole ratio of NaNO₃ to CaCO₃ is 2 : 1
Therefore; Number of moles of NaNO₃ = Moles of CaCO₃ × 2
Number of moles of NaNO₃ = 0.25 × 2 = 0.5 moles
Step 3: Calculate formula units of NaNO₃
We need to know that 1 mole of a compound contains formula units equivalent to the Avogadro's constant.
1 mole of a compound contains [tex]6.022 \times 10^{23}[/tex] formula units
Therefore; 0.5 moles of NaNO₃ will have;
= 0.5 × [tex]6.022 \times 10^{23}[/tex] formula units
= 3.011 [tex]\times 10^{23}[/tex] formula units
