Respuesta :
Explanation:
Relation between density and pressure is as follows.
[tex]\rho = \frac{P}{RT}[/tex]
P = [tex](32 lb/in^{2} + 14.7 lb/in^{2}) \times 144 in^{2}/ft^{2}[/tex]
= 6724.8 [tex]lb/ft^(2)[/tex]
Value of R = 1716 [tex]ft.lb/slug ^{o}R[/tex]
T = [tex](75 + 460)^{o}R[/tex]
Now, we will calculate the density as follows.
[tex]\rho = \frac{6724.8}{1716 \times 535}[/tex]
= 0.007325 [tex]slugs/ft^{3}[/tex]
Therefore, density of the air is 0.007325 [tex]slugs/ft^{3}[/tex].
Now, we will calculate the weight of the air as follows.
W = [tex]\rho gV[/tex]
= [tex]0.007325 \times 9.8 \times 3[/tex]
= 0.215 lbf
Therefore, weight of the tire in air is 0.215 lbf.
