Answer:
Step-by-step explanation:
The probability of having high blood pressure is 17%.
We need to find the probability of 2 or fewer have high blood pressure.
Possibility 1: No one have high blood pressure.
The probability is [tex]{\frac{100 -17}{100} }^{10} = {\frac{83}{100} }^{10}[/tex].
Possibility 2: Only one have high blood pressure.
The probability is [tex]{\frac{83}{100} }^9 \times \frac{17}{100}[/tex].
Possibility 3: 2 among the 10 have the high blood pressure.
[tex]{\frac{83}{100} }^8 \times {\frac{17}{100} }^2[/tex].
Any of the possibilities can happen.
Hence, the required probability is [tex]{\frac{83}{100} }^9 \times \frac{17}{100}[/tex] + [tex]{\frac{83}{100} }^8 \times {\frac{17}{100} }^2[/tex] + [tex]{\frac{83}{100} }^{10}[/tex].