Given that,
[tex]Radius = 5\frac{2}{5}\ inches = \frac{27}{5}\ inches[/tex]
To find: circumference
[tex]C = 2 \pi r[/tex]
Where, r is the radius of disc
Therefore,
[tex]C = 2 \times 3.14 \times \frac{27}{5}\\\\C = 6.28 \times 5.4\\\\C = 33.912[/tex]
[tex]C \approx 34[/tex]
Thus the circumference of flying disc is 34 inches