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Consider a thermal energy reservoir at 1500 K that can supply heat at a rate of 150,000 kJ/h. Determine the exergy of this supplied energy, assuming an environment temperature of 25°C.

Respuesta :

Answer:

exergy = 33.39 kW

Explanation:

given data

thermal energy reservoir T2 = 1500 K

heat at a rate = 150,000 kJ/h = [tex]\frac{15000}{3600}[/tex] kW =  41.67 kW

environment temperature T1 = 25°C = 298 K

solution

we get here maximum efficiency that is  reversible efficiency is express as

reversible efficiency = 1 - [tex]\frac{T1}{T2}[/tex]    ...............1

reversible efficiency = 1 - [tex]\frac{298}{1500}[/tex]  

reversible efficiency =  0.80133

and

the exergy of this supplied energy that is

exergy  = efficiency × hat supply   ................2

exergy = 0.80133 × 41.67 kW

exergy = 33.39 kW

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