Respuesta :
Answer:
30.1 m/s
Step-by-step explanation:
For a point in uniform circular motion, the relationship between angular speed and linear speed is given by
[tex]v=\omega r[/tex]
where
v is the linear speed
[tex]\omega[/tex] is the angular speed
r is the distance of the point from the axis of rotation
In this problem, we have:
[tex]\omega=4800 rpm[/tex] is the angular speed, in revolutions/minute
Converting into radians per second,
[tex]\omega=4800 \frac{rev}{min}\cdot \frac{2\pi rad/rev}{60 s/min}=502.4 rad/s[/tex]
The diameter of the CD is
d = 120 mm
So the radius is
r = 60 mm = 0.06 m
Therefore, a point at the outer edge of the disc has a distance of
r = 0.06 m from the axis.
Therefore, its linear speed is:
[tex]v=\omega r=(502.4)(0.06)=30.1 m/s[/tex]
Answer: Linear speed = 1809.55736847 m/min
Step-by-step explanation:
We will use the formula v = ωr
where
- v = the linear speed =
- ω = the angular speed = 4800 RPM = [tex]4800\cdot2\pi=9600\pi[/tex] radians/min.
- r = the distance of the point from the axis of rotation = radius = [tex]\frac{120}{2}=60[/tex] mm = 0.06 m.
So, the linear speed is:
[tex]v=9600\pi\cdot0.06=1809.55736847[/tex] m/min.
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