Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through the surface of the cube.

Respuesta :

To solve this problem, we will apply the concepts related to Gaus' law that establishes that the electric flow through a surface is given by the charge of the object on the Vacuum permittivity. Mathematically this would be

[tex]\phi = \frac{Q_{net}}{\epsilon_0}[/tex]

We must bear in mind that the net charge with the difference of the two charges given, therefore, replacing,

[tex]\phi = \frac{(15-40)*10^{-12}C}{8.85*10^{-12}C^2/Nm^2}[/tex]

[tex]\phi = 2.82WB[/tex]

Negative sign indicate flux is inward the surface

The net electric flux through the surface of the cube is 2.82 WB.

Gaus law:

Here we applied the Gaus law where the electric flow via the surface should be created by the charge of the object on the Vacuum permittivity

So, here the net electric flux should be

= (15-40)*10^-12C/8.85*10^-12C^2/Nm^2

= 2.82 WB

Here the negative sign represent the flux should be inward the surface.

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