Answer:
[tex]A=77.04\ in^2[/tex]
Step-by-step explanation:
we know that
The area of the shaded sections is equal to the area of the circle minus the area of the triangle
so
[tex]A=\pi r^{2} -\frac{1}{2}(b)(h)[/tex]
where
[tex]r=12/2=6\ in[/tex] ----> the radius is half the diameter
[tex]b=12\ in\\h=6\ in[/tex]
substitute
[tex]A=(3.14)6^{2} -\frac{1}{2}(12)(6)[/tex]
[tex]A=77.04\ in^2[/tex]
