Answer:
The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.
Step-by-step explanation:
Plane-1 = Boston, Massachusetts - Seattle, Washington at 10:00 AM
Plane-2= Seattle, Washington - Boston, Massachusetts at 11:00 AM
Speed of plane-1 = 300 mile/hour
Distance covered by plane-1 in 1 hour = 300 mile/h × 1 h = 300 mile
Distance between plane-1 and plane 2 after 1 hour :
= 3000 mile - 300 mile = 2700 mile
Let the distance covered by plane-1 after 1 hour be x in t time where it will pass plane-2.
Let the distance covered by plane-2 be y in t time where it will pass plane-1.
x + y = 2700 ...[1]
Speed of plane-1 = 300 mile/hour
[tex]300 mile/h=\frac{x}{t}[/tex]..[2]
Speed of plane-2 = 300 mile/hour
[tex]300 mile/h=\frac{y}{t}[/tex]..[3]
Putting value of t from [2] in [3];
[tex]t=\frac{x}{300 mile/h}[/tex]
[tex]300 mile/h=\frac{y}{\frac{x}{300 mile/h}}[/tex]
[tex]\frac{x}{300 mile/h}=\frac{y}{300 mile/h}[/tex]
x = y
In [1] put x = y
y + y = 2700 miles
2y = 2700 miles
y = 1,350 mile
For the value of t, put the value of y in [3]:
[tex]t=\frac{1,350 mile}{300 mile/h}=4.5 hour[/tex]
The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.
