Answer:
The angle of the incline above horizontal is 17.81 degrees.
Explanation:
Given that,
Mass of the object, m = 4 kg
Acceleration of the object above the incline, [tex]a=3\ m/s^2[/tex]
We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :
[tex]F_{net}=mg\ sin\theta[/tex]
[tex]ma=mg\ sin\theta[/tex]
[tex]a=g\ sin\theta[/tex]
[tex]sin\theta=\dfrac{a}{g}[/tex]
[tex]sin\theta=\dfrac{3}{9.8}[/tex]
[tex]\theta=17.81^{\circ}[/tex]
So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.
The angle of the incline above horizontal will be "17.81°".
The force thus prevents one solid item from slipping or tumbling more than another. Frictional forces, including the adhesion required to walk without slipping, can be useful, although they can provide a significant amount of resistance to movement.
According to the question,
Object's mass, m = 4 kg
Object's acceleration, a = 3 m/s²
As we know,
→ Net force, [tex]F_{net}[/tex] = mg Sin[tex]\Theta[/tex]
or,
→ ma = mg Sin[tex]\Theta[/tex]
a = g Sin[tex]\Theta[/tex]
Angle, Sin[tex]\Theta[/tex] = [tex]\frac{a}{g}[/tex]
By substituting the values,
= [tex]\frac{3}{9.8}[/tex]
= [tex]17.81^{\circ}[/tex]
Thus the above answer is correct.
Find out more information about acceleration here:
https://brainly.com/question/26408808
