Respuesta :

ajeigbeibraheem

Answer:

153.2 J

Explanation:

Let's first list our given parameters;

mass (m) of the block = 10 kg

which slides down ( i.e displacement) = 2 m

kinetic coefficient of friction (μk) = 0.2

In the diagram shown below;  if we take an integral look at the component of force in the direction of the displacement; we have

[tex]F_x=[/tex] Fcos 40°

[tex]F_x=[/tex] 100 (cos 40°)

[tex]F_x=[/tex] 76.60 N

Workdone by the friction force can now be determined as:

W = [tex]F_x[/tex] × displacement

W = 76.60 × 2

W = 153.2 J

∴  the work done by the friction force = 153.2 J

Ver imagen ajeigbeibraheem
Lanuel

The work done by the friction force is equal to 39.2 Nm.

Given the following data:

  • Mass = 10 kg
  • Displacement = 2 meters
  • Coefficient of kinetic friction = 0.2

To determine the work done by the friction force:

First of all, we would find the force of kinetic friction acting on the object.

Mathematically, the force of kinetic friction is given by the formula;

[tex]F_k = umg\\\\F_k = 0.2 \times 10 \times 9.8\\\\F_k =19.6\;Newton[/tex]

For the work done by the friction force:

[tex]Work\;done = F_k \times displacement[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 19.6 \times 2[/tex]

Work done = 39.2 Nm

Read more: https://brainly.com/question/22599382

Otras preguntas