The temperature of the system is 141.36K.
According to the universal gas law, the pressure of a gas is directly proportional to the absolute temperature and number of moles of the gas and inversely proportional to the volume of the gas.
So in equation format,
[tex]\frac{P\times V}{n\times T}[/tex] =constant.
Or[tex]\frac{P\times V}{n\times T}[/tex]= R.
Here R is called the universal gas constant which has different values in different units.
Here the unit of volume is in litres and unit of pressure is in atmosphere.
So. Value of R comes as =0.082057[tex]\frac{L\times atm} {K\times mole}[/tex].
So, according to the question,
P is 5.8atm, V is 12 litres and n is 6 moles.
So, [tex]5.8\times12[/tex] = [tex]6\times0.082057\times T[/tex].
Or, T = [tex]\frac{5.8\times12} {6\times0.082057}[/tex].
Or, T = 141.36.
So,the temperature of the system is 141.36K
