Answer:
The time taken by the object to reach the ground is 0.58 seconds.
Explanation:
Given that,
An object was released from rest at height of 1.65 m with respect to ground. We need to find the time taken by the object to reach the ground. Initial speed of the object is 0 as it is at rest. It will move downward under the action of gravity such that, the distance covered by the object is given by :
[tex]d=ut+\dfrac{1}{2}gt^2[/tex]
[tex]d=\dfrac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\dfrac{2d}{g}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 1.65}{9.8}}[/tex]
t = 0.58 seconds
So, the time taken by the object to reach the ground is 0.58 seconds. Hence, this is the required solution.
