Answer:
 t = 0.113 s
Explanation:
In this exercise we can use Newton's second law
X Axis       F - fr = ma
Y Axis      N –W = 0
          N = W = m g
The force of friction is
         fr = μ N
We replace
         F - μ m g = m a
         a = (F- μ mg) / m
         a = (2650 - 0.45 300 9.8) / 300
         a = 4,423 m / s2
Now we can use the kinematics expressions, where we assume that the system starts with zero speed
        v = v₀ + a t
        t = v / a
        t = 0.5 / 4.423
        t = 0.113 s