Answer:
True
Explanation:
The linkage relation of two genes can be determined on the basis of calculating recombination frequency.
If the recombination frequency value is greater than 50% then the genes are not linked and if the value is less than 50% then the genes are linked.
In the given question, the crossover gametes formed will be Ab = 100
and aB= 106.
Therefore,
[tex]\dfrac{recombinant\ progenies}{ Total\ progeny}\times 100\\\\\dfrac{100 +106}{100+106+45+50}\times 100\\\\=\dfrac{206}{301}\times 100\\\\= 68.43\%[/tex]
Since the recombinant frequency value is larger than 50% therefore the genes do not show linkage.
Thus, True is the correct answer.
