Respuesta :
Explanation:
Ka is the acid dissociation constant. pKa is simply the -log of this constant.
Mathematically;
pKa = - log Ka
Ka = 10^-pKa
a. acid a has a pka of 6.0 what is its ka?
Ka = 10^-6 = 10⁻⁶
b. acid b has a pka of 8.60 whats its ka?
Ka = 10^-8.6 = 2.51e⁻⁹
c. acid c has a pka of -2.0 whats its ka?
Ka = 10^-(-2) = 10^2 = 100
a. The ka when acid a has a pka of 6.0 should be 10^-6 = 10⁻⁶.
b. The ka when acid b has a pka of 8.60 be 10^-8.6 = 2.51e⁻⁹.
c. The ka when acid c has a pka of -2.0 be 10^-(-2) = 10^2 = 100.
Calculation of dissociation constants:
Since
Ka represent the acid dissociation constant.
pKa is simply the -log of this constant.
So in terms of Mathematically;
pKa = - log Ka
So,
Ka = 10^-pKa
a. Ka = 10^-6 = 10⁻⁶
b. Ka = 10^-8.6 = 2.51e⁻⁹
c. Ka = 10^-(-2) = 10^2 = 100
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