Respuesta :
Answer:
Therefore the equation of required line is
x-3y-6=0
Step-by-step explanation:
Line: A line can formed by joining two points. To make a line we need at least two point.
A defined portion of a line is known as line segment.
If a line passes through a point then the point will be satisfy the line.
It means (p,q) lies on a line ax+by+c=0
Then ap+bq+c=0 [putting x=p and y=q]
If two lines are perpendicular to each other then the product of their slope is -1.
Given line is
y= 3x-2.
The above equation is in form of y = mx+c
Where m is the slope of the line.
Therefore the slope of the line is = 3
Let the slope of required line be m.
Since the given line and required line perpendicular to each other.
Then,
[tex]m\times 3=-1[/tex]
[tex]\Rightarrow m=-\frac{1}{3}[/tex]
If the a line passes through a point(x₁,y₁) and slope of that line is m₁.
The equation of line is
(y-y₁)=m₁(x-x₁)
Here x₁= -9 and y₁=5
Therefore the equation of required line is
[tex]y-5=-\frac{1}{3} [x-(-9)][/tex]
[tex]\Rightarrow 3y-15=-x-9[/tex]
[tex]\Rightarrow x-3y-6=0[/tex]
Answer:
y=\purpleC{-\dfrac{1}{3}}x \greenD{+2}y=−
3
1
x+2
Step-by-step explanation:
awd
