In guinea pigs, the gene for rough coat (R) is dominant over the gene for smooth coat is (r). the gene for black coat color (B) is dominant over the gene for albino (b). a heterozygous black, smooth-coated male is bred to a heterozygous black, rough-coated female. WHAT GENOTYPIC AND PHENOTYPIC RATIOS COULD YOU EXPECT AMONG THEIR OFFSPRING? USE A PUNNET SQUARE. (you can make a punnet square on google docks and then copy and paste on to this site) thank you!!!!

In guinea pigs, the gene for rough coat (R) is dominant over the gene for smooth coat is (r). the gene for black coat color (B) is dominant over the gene for albino (b). a heterozygous black, smooth-coated male is bred to a heterozygous black, rough-coated female. WHAT GENOTYPIC AND PHENOTYPIC RATIOS COULD YOU EXPECT AMONG THEIR OFFSPRING? USE A PUNNET SQUARE.

Bbrr x BbRr= BBRr, BbRr, BbRr, bbrr 3:1

Explanation:

From the crossing above, the offspring will be 3 dominant heterozygous black rough coat and 1 homozygous albino smooth coat

coge4eva coge4eva · Answer 2 · 2020-03-01T17:08:13+01:00

Answer: The genotypic ratio of the offsprings is 2BBRr: 4BbRr: 2BBrr: 4Bbrr: 2bbRr: 2bbrr.

The phenotypic ratio is 6 Black and rough coat : 6 Black and smooth coat : 2 Albino and rough : 2 albino and smooth coat.

Explanation: The genotype of a heterozygous black, smooth-coated male is BbRr while the genotype of a heterozygous black, rough-coated female is BbRr.

A cross between them will produce sixteen offsprings with six possible genotypes: BBRr, BbRr, BBrr, Bbrr, bbRr and bbrr.

Six of the offsprings will be black and rough coated, six of them will be black and smooth coated, two of them will be albino and rough coated while two will be albino and smooth coated.

See attached punnet square for more details