The molar latent enthalpy of boiling of iron at 3330 K is  ΔH = 342 [tex]\times[/tex] 10^3 J.
Explanation:
Molar enthalpy of fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.
           d ln p = (ΔH / RT^2) dt
          (1/p) dp = (ΔH / RT^2) dt
          dp / dt = p (ΔH / RT^2) = 3.72 [tex]\times[/tex] 10^-3
         (p) (ΔH) / (8.31) (3330)^2 = 3.72 [tex]\times[/tex] 10^-3
             ΔH = 342 [tex]\times[/tex] 10^3 J.
