A chemist adds of a M sodium nitrate solution to a reaction flask. Calculate the mass in grams of sodium nitrate the chemist has added to the flask. Round your answer to significant digits.

Respuesta :

The question is incomplete. The complete question is:

A chemist adds 390.0 mL of a 2.1M sodium nitrate [tex]NaNO_3[/tex] solution to a reaction flask. Calculate the mass in grams of sodium nitrate the chemist has added to the flask. Round your answer to 2 significant digits.

Answer: 70 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]NaNO_3[/tex]  = [tex]\frac{\text {given mass}}{\text {Molar Mass}}=\frac{xg}{85g/mol}[/tex]

Now put all the given values in the formula of molality, we get

[tex]2.1M=\frac{x\times 1000}{85\times 390.0}[/tex]

[tex]x=70g[/tex]

Therefore, the mass in grams of sodium nitrate the chemist has added to the flask is 70 grams

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