Answer:
The concentration would be 0.0302 M.
Explanation:
The reaction follows a first-order in cyclopropane.
Rate = kC = change in concentration/time
Let the concentration of cyclopropane after 235 minutes be y
k is rate constant = 3.36×10^-5 s^-1
Initial concentration = 0.0445 M
Change in concentration = (0.0445 - y)
Time = 235 minutes = 235 × 60 = 14,100 s
3.36×10^-5y = (0.0445 - y)/14,100
3.36×10^-5y × 14,100 = 0.0445 - y
0.47376y = 0.0445 - y
0.47376y + y = 0.0445
1.47376y = 0.0445
y = 0.0445/1.47376 = 0.0302 M
Explanation:
r =−dA/dt
= k[A]
Where,
k = rate constant
= 3.36×10^-5 s^-1
Initial concentration, Ao = 0.0445 M
Change in concentration, dA = (0.0445 - y), y is the concentration at time, t (At)
Time,t = 235 min
= 235 × 60
= 14,100 s
3.36×10^-5 × y = (0.0445 - y)/14,100
3.36×10^-5y × 14,100 = 0.0445 - y
0.4738 × y = 0.0445 - y
0.4738y + y = 0.0445
1.4738y = 0.0445
y = 0.0445/1.4738
= 0.0302 M
