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A storm sewer is carrying snow melt containing 1.2 g/L of sodium chloride into a small stream. The stream has a naturally occurring sodium chloride concentration of 20 mg/L. If the storm sewer flow rate is 2000 L/min and the stream flow rate is 2 m3/s, what is the concentration of salt in the stream after the discharge point? Assume that the flow is completely mixed, the salt is nonreactive, and the system is at steady state

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beingteenowfmao

Answer:

Given Data:

concentration of sewer Csewer = 1.2 g/L

converting into mg/L = Csewer = 1.2 g/L x 1000 mg/g = 1200 mg/L

flow rate of sewer Qsewer = 2000 L/min

concentration of sewer Cstream = 20 mg/L

flow rate of sewer Qstream = 2m3/s

converting Q into L/min = 2m3/s x 1000 x 60 = 120000 L/min

mass diagram is

Ver imagen beingteenowfmao
Ver imagen beingteenowfmao
Cricetus

The concentration of salt will be "39344 mg/L".

According to the question,

Storm sewer flow rate,

  • [tex]Q_{se} = 2000 \ L/min[/tex]

Stream flow rate,

  • [tex]Q_{st} = 2 \ m^3/s[/tex]

Sodium chloride,

  • [tex]C_{se} = 1.2 \ g/L[/tex]

Sodium chloride concentration,

  • [tex]C_{st} = 20 \ mg/L[/tex]

As we know,

→   [tex]Q = Q_{st} +Q_{se}[/tex]

→ [tex]Q_{st} = 2 \ m^3/s\times 1000 \ L/m^3\times 60 \ s/min[/tex]

→    [tex]Q = 120000+2000[/tex]

→        [tex]= 122000 \ L/min[/tex]

hence,

→ [tex]C_{min} = \frac{Q_{st}\times C_{st}+Q_{se} \ C_{se}}{Q}[/tex]

→          [tex]=\frac{120000\times 20+2000\times 1200}{122000}[/tex]

→          [tex]= 39344 \ mg/L[/tex]    

Thus the above response is right.

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https://brainly.com/question/17211430

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