Write a balanced half-reaction for the oxidation of liquid water H2O to aqueous hydrogen peroxide H2O2 in basic aqueous solution. Be sure to add physical state symbols where appropriate.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion [tex](OH^-)[/tex] at that side where the less number of hydrogen are present.

Now balance the charge.

The half reaction is :

[tex]H_2O(l)\rightarrow H_2O_2(aq)[/tex]

Now balance the oxygen atoms.

[tex]H_2O(l)\rightarrow H_2O_2(aq)+H_2O(l)[/tex]

Now balance the hydrogen atoms.

[tex]H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)[/tex]

Now balance the charge.

[tex]H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)+2e^-[/tex]

The balanced half-reaction in a basic solution will be,

[tex]2OH^-(aq)\rightarrow H_2O_2(aq)+2e^-[/tex]

AFOKE88 AFOKE88 · Answer 2 · 2021-11-19T07:09:15+01:00

The balanced half-reaction for the oxidation of liquid water H2O to aqueous hydrogen peroxide H2O2 in basic aqueous solution

2OH- → H2O2(aq) + 2e-

Since liquid water undergoes oxidation to form hydrogen peroxide, then let us place the water on the reactants side and hydrogen peroxide on the products side;

H2O(l) → H2O2(aq)

Now, let us balance the oxygen atoms to get;

2H2O(l) → H2O2(aq)

Now,let us balance the number of hydrogen H atoms by putting 2 protons on the products side

2H2O(l) → H2O2(aq) + 2H+(aq)

We will now balance the number of electrons to get;

2H2O(l) → H2O2(aq) + 2H+(aq) + 2e-

To have a basic solution, we must add two hydroxide ions to both sides;

2H2O(l) + 2OH- → H2O2(aq) + 2H+(aq) + 2e- + 2OH-

Hydroxide ions react with hydrogen ions on the product side to form water. Thus;

2H2O(l) + 2OH- → H2O2(aq) + 2H2O(l) + 2e-

2H2O will cancel out from both sides to get;

2OH- → H2O2(aq) + 2e-

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