Respuesta :
Answer:
0.1679 M is the molarity of the diluted sodium hypochlorite solution.
Explanation:
Concentration of a stock sodium hypochlorite solution = 6.25%(w/v)
This means that 6.25 grams of sodium hypochlorite is present in 100 mL of solution.
Moles of sodium hypochlorite = [tex]\frac{6.25 g}{74.44 g/mol}=0.08396 mol[/tex]
Volume of the solution = 100 mL = 0.100 L ( 1 mL=0.001 L)
[tex]Molarity=\frac{Moles}{\text{Volume in L}}[/tex]
Molarity of the solution = [tex]\frac{0.08396 mol}{0.100 L}=0.8396 M[/tex]
Molarity of the of a stock sodium hypochlorite solution =[tex]M_1= 0.8396 M[/tex]
Volume of stock sodium hypochlorite solution taken for dilution =[tex]V_1= 10 mL[/tex]
Molarity of stock sodium hypochlorite solution after dilution = [tex]M_2=?[/tex]
Volume of stock sodium hypochlorite solution after dilution = [tex]V_2=50 mL[/tex]
[tex]M_1V_1=M_2V_2[/tex]
[tex]M_2=\frac{M_V_1}{V_2}=\frac{0.8396 M\times 10 mL}{50 mL}=0.1679 M[/tex]
0.1679 M is the molarity of the diluted sodium hypochlorite solution.
