Complete question:
Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure.
If the radius of curvature of the bump is 52 m, find the apparent weight of a 68-kg person in your car as you pass over the top of the bump.
Answer:
the apparent weight is 34 N
Explanation:
Given:
radius of curvature of the bump = 52 m
mass of the person = 68 kg
Apparent weight of the person due to centripetal acceleration which acts inward, is calculated as follows;
From Newton's second law of motion, apparent weight = [tex]F_g - F_a[/tex]
[tex]=M_g-M_a\\\\= M(g-\frac{v^2}{r})\\\\= 68(9.8-\frac{22^2}{52})\\\\=68 (9.8 -9.3)\\\\= 68(0.5)\\\\=34 N[/tex]
Therefore, the apparent weight is 34 N
