Answer:
0.6749 M is the concentration of B after 50 minutes.
Explanation:
A → B
Half life of the reaction = [tex]t_{1/2}=25 minutes[/tex]
Rate constant of the reaction = k
For first order reaction, half life and half life are related by:
[tex]k=\frac{0.693}{t_{1/2}}[/tex]
[tex]k=\frac{0.693}{25 min}=0.02772 min^{-1}[/tex]
Initial concentration of A = [tex][A]_o=0.900 M[/tex]
Final concentration of A after 50 minutes = [tex][A]=?[/tex]
t = 50 minute
[tex][A]=[A]_o\times e^{-kt}[/tex]
[tex][A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}[/tex]
[A] = 0.2251 M
The concentration of A after 50 minutes = 0.2251 M
The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M
0.6749 M is the concentration of B after 50 minutes.