Given that the density of CaO ( s ) is 3.34 g/cm 3 and that the length of an edge of a unit cell is 481 pm, determine how many formula units of CaO there are in a unit cell.

Respuesta :

Answer: The number of formula units of CaO in one unit cell are 4

Explanation:

To calculate the number of formula units, we use the equation used to calculate the density of metal, which is:

[tex]\rho=\frac{Z\times M}{N_{A}\times a^{3}}[/tex]

where,

[tex]\rho[/tex] = density  of CaO = [tex]3.34g/cm^3[/tex]

Z = number of atom in unit cell = ?

M = atomic mass of CaO = 56 g/mol

[tex]N_{A}[/tex] = Avogadro's number = [tex]6.022\times 10^{23}[/tex]

a = edge length of unit cell = [tex]481pm=481\times 10^{-10}cm[/tex]    (Conversion factor:  [tex]1cm=10^{10}pm[/tex]  )

Putting values in above equation, we get:

[tex]3.34=\frac{Z\times 56}{6.022\times 10^{23}\times (481\times 10^{-10})^3}\\\\Z=3.997\approx 4[/tex]

Hence, the number of formula units of CaO in one unit cell are 4