Explanation:
Chemical equation for the given reaction is as follows.
[tex]KSCN \rightarrow K^{+} + SCN^{-}[/tex]
KSCN is present 35.0 ml of 0.06 M. Hence, we will calculate the total milimoles of [tex]SCN^{-}[/tex] as follows.
[tex]35.0 \times 0.06 M[/tex]
= 2.1 mmoles
Now, we will calculate the total volume in mixture as follows.
Total volume = (35 + 35 + 45) mL
= 115 ml
Hence, initial concentration of [tex]SCN^{-}[/tex] will be calculated as follows.
= [tex]\frac{2.1 mmol}{115 ml}[/tex]
= 0.0182 M
Thus, we can conclude that the initial concentration of [tex]SCN^{-}[/tex] in the mixture is 0.0182 M.
