Respuesta :
Answer:
The pH of this solution is 13.515
Explanation:
Step 1: Data given
Number of moles Ba(OH)2 = 0.0890 moles
Volume = 545 mL
Step 2: Calculate moles OH
Ba(OH)2 → Ba^2+ + 2OH-
In 1 moles Ba(OH)2 we have 2 moles OH-
In 0.0890 moles Ba(OH)2 we have 2*0.0890 = 0.178 moles OH-
Step 3: Calculate concentration of OH-
[OH-] = moles / volume
[OH-] = 0.178 moles / 0.545 L
[OH-] = 0.327 M
Step 4: Calculate pOH
pOH = -log[OH-]
pOH = -log(0.327)
pOH = 0.485
Step 5: Calculate pH
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.485
pH = 13.515
The pH of this solution is 13.515
The pH of this solution is 13.515
Given:
Number of moles Ba(OH)₂ = 0.0890 moles
Volume = 545 mL
Calculation for moles:
[tex]Ba(OH)_2[/tex] → [tex]Ba^{2+} + 2OH^-[/tex]
In 1 moles Ba(OH)₂ we have 2 moles OH-
In 0.0890 moles Ba(OH)₂ we have 2*0.0890 = 0.178 moles OH-
Calculation for concentration:
[OH-] = moles / volume
[OH-] = 0.178 moles / 0.545 L
[OH-] = 0.327 M
Calculation of pOH:
pOH = -log[OH-]
pOH = -log(0.327)
pOH = 0.485
Calculation of pH:
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.485
pH = 13.515
Thus, the pH of this solution is 13.515.
Find more information about pH here:
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