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Estimate the change in temperature of 5 m3 of air, due to an increase in pressure of 50 kPa. The initial temperature of the air is 158C at atmospheric pressure.

Respuesta :

Answer:

change in temperature is 142°

Explanation:

given data

volume v = 5 m³

increase in pressure = 50 kPa

initial temperature of  air = 15° C = 288 K

solution

here initial pressure P1 = Patm

initial pressure = 101325 Pa

so

final pressure will be

final pressure P2 = P1 + 50 kPa

final pressure P2 = 101.325 + 50

final pressure P2 = 151325 Pa

and

now we get final temperature so keep volume constant

[tex]\frac{P1}{T1} = \frac{P2}{T2}[/tex]    .............1

[tex]\frac{101325}{288} = \frac{151325}{T2}[/tex]

T2 = 430.11 K = 157.11°

so here change in temperature is

change in temperature = T2 - T 1

change in temperature = 157.11 - 15

change in temperature is 142°

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