Answer:
Explanation:
CO(g) + NH3(g) ⇌ HCONH2(g)
-vessel iniatial 1 2 0
concentration
-equillibrium 1-x 2-x x
concentration
[tex]K_{C} = (CO)\times (NH_{3})/ (HCONH_{2})[/tex]
0.860 = (1-x)(2-x) / x
[tex]x^{2}-3.86x+2[/tex]
[tex]x = 3 , 0.5[/tex]
concentration of HCONH2 at equillibrium is 0.5 M