Respuesta :
Answer:
We need 0.50 L of O2 to react
Explanation:
Step 1: Data given
Volume of carbon monoxide (CO) = 1.0 L (STP)
Step 2: The balanced equation
2CO(g) + O2(g) → 2CO2(g)
Step 3: Calculate moles CO
22.4 L = 1.0 mol
1.0 L = 1.0 / 22.4 L = 0.0446 moles
Step 4: Calculate moles O2
For 2 moles CO we need 1 mol O2 to produce 2 moles CO2
For 0.0446 moles CO we need 0.0446/2 = 0.0223 moles O2
Step 5: Calculate volume O2
1.0 mol = 22.4 L
0.0223 moles = 0.50 L
We need 0.50 L of O2 to react
The volume of oxygen required to react with CO has been 0.5 L.
The volume of a mole of gas at STP has been 22.4 L. The stoichiometric coefficient in the balanced chemical equation gives the information of moles of reactant and product in the reaction.
Computation for the volume of oxygen
The volume of CO reacted has been 1 L. The moles of CO reacted has been given as:
[tex]\rm 22.4\;L=1\;mol\\1\;L=\dfrac{1}{22.4}\;\times\;1\;mol\\ 1\;L=0.044\;mol[/tex]
The moles of CO reacted has been 0.044 mol.
According to balanced chemical equation, the moles of oxygen reacted with 2 moles of CO has been 1.
The moles of oxygen reacted with 0.044 mol of CO has been:
[tex]\rm 2\;mol\;CO=1\;mol\;O_2\\0.044\;mol\;CO=\dfrac{1}{2}\;\times\;0.044\;mol\;O_2\\ 0.044\;mol\;CO=0.022\;mol\;O_2[/tex]
The moles of oxygen reacted has been 0.022 mol. The volume of oxygen has been given as:
[tex]\rm 1\;mol=22.4\;L\\0.022\;mol=\dfrac{22.4}{1}\;\times\;0.022\;L\\ 0.022\;L=0.5\;L[/tex]
The volume of oxygen required to react with CO has been 0.5 L.
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