Answer:
Minimum DC current [tex]= 9[/tex] Ampere
Voltage [tex]= 74.862[/tex] V
Explanation:
Here in this questions three resistors are used in series
Resistance of cap circuit
[tex]R_1 =\frac{ 8* 2.3}{6} \\R_1 = 3.067[/tex]
Here [tex]2.3[/tex] is the resistance per cap
Resistance of bus wire
[tex]R_2 = \frac{50 * 4.02 }{1000} \\R_2 = 0.201[/tex]
Where [tex]4.02[/tex] is the resistance per [tex]1000[/tex] feet of bus wire of gauge 16
Resistance of firing line
[tex]R_3 = \frac{(2*1000)* 2.525}{1000} \\R_3 = 5.05[/tex]
where [tex]2.525[/tex] is the resistance per [tex]1000[/tex] feet of bus wire of gauge 14
Total resistance is equal to
[tex]R = R_1 + R_2 + R_3\\R = 3.067 + 0.201 + 5.05 \\R = 8.318[/tex]
Current in firing line is equal to
[tex]1.5 * 6\\= 9[/tex]
Voltage is equal to product of resistance and current
[tex]= 9 * 8.318\\= 74.862[/tex]
