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Which equation has the solutions x = 1+ V5?
A) x^2 + 2х + 4 = 0
B) x^2 — 2х + 4 = 0
C) х^2 + 2х – 4 = 0
D) x^2— 2х – 4 = 0

Respuesta :

dannielle

Answer:

x^2-2x-4=0

Δ=2^2-4*1*(-4)

Δ=4+16=20

VΔ=2V5

x1= (2+2V5)/2=1+V5

the answer is D

Step-by-step explanation:

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