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If you have a list of all three digit numbers that can be written using only the digits 1,2,3,4, and 5.
What is the probability that a randomly chosen number in the list has AT LEAST one 4 as a digit?

Respuesta :

amna04352

Answer:

61/125 or 0.488

Step-by-step explanation:

Total = 5×5×5 = 125

Numbers with no 4 = 4×4×4 = 64

Atleast one 4= 125-64 = 61

P(atleast one 4) = 61/125 or 0.488
61/125!! Hope this helps!!!!

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