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You have a 2.00 kg block of lead. Lead melts at 327.5°C. Cpb = 130.0 J/kg*C and △Hj for lead is 2.04x10^4 J/kg . Say you start at room temperature (25.0°C). How much heat must you transfer to melt all the lead?

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samuelonum1

Answer:40,800joules

Explanation:given

Masss of lead is2kg

Latent heat for lead 2.04*10^4

Using the formula

Q=ml

Where Q is Quantity of heat required to melt the lead

=2*2.04*10^4= 40,800 joules

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