Step-by-step explanation:
[tex] \frac{9x - 5}{4x - 1} + ( \frac{3x + 8}{4x - 1} - \frac{5x + 3}{4x - 1} ) \\ \\ = \frac{9x - 5}{4x - 1} + ( \frac{(3x + 8) - (5x + 3)}{4x - 1}) \\ \\ = \frac{9x - 5}{4x - 1} + ( \frac{3x + 8 - 5x - 3}{4x - 1}) \\ \\ = \frac{9x - 5}{4x - 1} + \frac{5 - 2x }{4x - 1} \\ \\ = \frac{9x - 5 + 5 - 2x}{4x - 1} \\ \\ \red{ \boxed{ \therefore \: \frac{9x - 5}{4x - 1} + ( \frac{3x + 8}{4x - 1} - \frac{5x + 3}{4x - 1} )= \purple{\frac{7x}{4x - 1} }}} \\ [/tex]
