Respuesta :
Answer and Step-by-step explanation:
[tex]Good~Day![/tex]
[tex]Let's~answer~your~question~shall~we?[/tex]
Answer for the first question:
[tex]=\frac{3(x+3)}{12} +\frac{4(x-5)}{12}[/tex]
[tex]=\frac{x(x+3)~+~4(x-5)}{12}[/tex]
[tex]=\frac{3x+~9+~4x~4-20}{12}[/tex]
[tex]=\frac{7x~-~11}{12}[/tex]
Answer:
→ [tex]\frac{7x~-~11}{12}[/tex]
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Answer for the second question:
[tex]\frac{x-4}{(x+4)~(x-4)} ~+ ~\frac{2(x+4)}{(x+4)~(x-4)}[/tex]
[tex]=\frac{x-4~+~2~(x+4)}{(x+4)~(x-4)} =\frac{x-4~+~2x~+8}{(x+4)~(x-4)}[/tex]
[tex]=\frac{3x~+~4}{(x+4)~(x-4)}[/tex]
Answer:
→ [tex]\frac{3x~+~4}{(x+4)~(x-4)}[/tex]
Answer:
1) (7x-11)/12
2) (3x+4)/(x²-16)
Step-by-step explanation:
1)
(x+3)/4 + (x-5)/3
Lcm: 12
[3(x+3) + 4(x-5)]/12
(3x+4x+9-20)/12
(7x-11)/12
2) 1/(x+4) + 2/(x-4)
Lcm: (x+4)(x-4) = x²-16
[(x-4)(1) + (x+4)(2)]/(x²-16)
(x-4+2x+8)/(x²-16)
(3x+4)/(x²-16)