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A 2.0 kilogram rifle initially at rest fires a 0.002 kilogram bullet. As the bullet leaves the rifle with a velocity of 500 meters per second , what is the momentum of the rifle -bullet system ?

Respuesta :

Raj1232

Answer:

1001

Explanation:

M=2.0+0.002=2.002kg

V=500m/s

p=?

p=M×V

p=2.002×500

p=1001

The momentum of the rifle bullet system is 1001 kg-m/s.

How do you calculate the momentum?

Given that the mass of the rifle is 2 kg and the mass of the bullet is 0.002 kg. The velocity of the bullet is 500 meters per second.

The total mass of the system is the sum of the mass of rifle and bullet. Hence

Mass [tex]m = 2.0 + 0.002[/tex]

Mass [tex]m = 2.002[/tex] kg.

The momentum of the rifle bullet system is the product of the total mass and velocity of the bullet.

Momentum = [tex]m\times v[/tex]

Momentum = [tex]2.002\times 500[/tex]

Momentum = [tex]1001 \;\rm kg-m/s[/tex]

Hence we can conclude that the momentum of the rifle bullet system is 1001 kg-m/s.

To know more about the momentum, follow the link given below.

https://brainly.com/question/14459931.

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