Answer:
a = negative 2, b = 4
Step-by-step explanation:
We want to find the value of a and b in the equation:
[tex](4 {x}^{a})^{b} = \frac{256}{ {x}^{8} } [/tex]
We rewrite the RHS to get:
[tex](4 {x}^{a})^{b} = 256{x}^{ - 8}[/tex]
[tex](4 {x}^{a})^{b} = {4}^{4} {x}^{ - 8}[/tex]
[tex](4 {x}^{a})^{b} = ( {4} {x}^{ - 2})^{4} [/tex]
We now compare to have a=-2 and b=4
