Respuesta :
Answer: 27, 28, 29 and 30
Step-by-step explanation:
The four consecutive numbers be n ,n+1 ,n+2 ,n+3. Their sum is 114.
Therefore, n+(n+1)+(n+2)+(n+3) = 114
4n+6=114
4n=108
n=108/4
n=27.
27+28+29+30 =114.
Answer: 27, 28, 29 and 30
Step-by-step explanation:
The four consecutive numbers be n ,n+1 ,n+2 ,n+3. Their sum is 114.
Therefore, n+(n+1)+(n+2)+(n+3) = 114
4n+6=114
4n=108
n=108/4
n=27.
27+28+29+30 =114.