Answer:
2.5/5V
Step-by-step explanation:
Given the expression for hang time t = 5Vh
A kite sailor has a hang time of 2.5 secs
Height of the kite’s sailor’s jump = ?
Therefore 2.5 = 5Vh
Divide both sides by 5V
2.5/5V = h
h = 2.5/5V
The height of the kite sailor's jump is [tex]\dfrac{5}{0.5V}[/tex] .
Given that,
"Hangtime" is the time you are suspended in the air during a jump. Your hang time t in seconds is given by the function t =0.5Vh,
Where h is the height (in feet) of the jump.
A kite sailor has a hang time of 2.5 seconds.
We have to determine,
The height of the kite sailor's jump.
According to the question,
Function t =0.5Vh,
A kite sailor has an hang time of 2.5 seconds.
Then,
The height of the kite sailor's jump is,
[tex]t = 0.5Vh\\\\5 = 0.5Vh\\\\h = \dfrac{5}{0.5V}[/tex]
Hence, The height of the kite sailor's jump is [tex]\dfrac{5}{0.5V}[/tex] .
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