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What is the solution to 4 Superscript log Subscript 4 Baseline (x + 8) Baseline = 4 squared
x = negative 8
x = negative 4
x = 4
x = 8

Respuesta :

kudzordzifrancis

Answer:

x = 8

Step-by-step explanation:

The given equation is

[tex] {4}^{ log_{4}(x + 8) } = {4}^{2} [/tex]

Recall that:

[tex] {p}^{ log_{p}(x) } = x[/tex]

Apply this property of logarithms to get:

[tex](x + 8) = {4}^{2} [/tex]

Simplify on the right,

[tex]x + 8 = 16[/tex]

Subtract 8 from both sides,

[tex]x = 16 - 8 = 8[/tex]

abidemiokin

These are inverse of exponential functions. The solution to the given function is 8

Logarithmic functions

These are inverse of exponential functions. Given the logarithmic expressions as shown:

[tex]4^{log_4(x+8)}=4^2[/tex]

Cancel the base to have:

[tex]log_4(x+8)=2[/tex]

Apply the law of logarithm to have;

[tex]x+8=4^2\\x+8=16[/tex]

subtract 8 from both sides

[tex]x = 16 - 8\\x = 8[/tex]

Hence the solution to the given function is 8

Learn more on log function here : https://brainly.com/question/10208274

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