Answer:
s = it+1/2 at²
s= 8×3+1/2 (10)(3)²
s = 24+45
s= 69
the object was thrown from a height of 69 meters
The maximum height of the object is 68.1 m.
How do you calculate the height?
Given that the initial velocity u of the object is 8 m/s and the time t taken by the object is 3 seconds to strike the ground. In this case, the acceleration a on the object is the acceleration due to gravity which is 9.8 m/s2.
The height of the object is calculated by the formula given below.
[tex]d = ut + \dfrac {1}{2}at^2[/tex]
[tex]d = 8 \times 3 + \dfrac {1}{2}\times 9.8 \times 3^2[/tex]
[tex]d = 68.1 \;\rm m[/tex]
Hence we can conclude that the maximum height of the object is 68.1 m.
To know more about the height and acceleration, follow the link given below.
https://brainly.com/question/13578440.
